PROBLEM 51 OF 75

Palindromic Substrings

Count all palindromic substrings, including duplicates by position.

PATTERNDynamic programmingState is the smallest information needed to finish.
SPOT THE SIGNAL

Why does this pattern fit?

FRAME · 1 OF 4

Restate the exact job

Count all palindromic substrings, including duplicates by position.

WHY THIS FITS

Each successful center expansion corresponds to one distinct substring occurrence.

COMPLEXITY

O(n²) time · O(1) space

COMMON FAILURE

Counting only maximal palindromes misses their palindromic interiors.

THE REASONING, IN ONE PLACE

How to solve Palindromic Substrings

The goal is to solve this problem from the pattern, not to memorize a finished answer. Use this as a check after your own attempt.

What the question asks

Count all palindromic substrings, including duplicates by position.

Why Dynamic programming fits

Each successful center expansion corresponds to one distinct substring occurrence.

State to maintain

A count and expansion pointers for odd/even centers.

Transition

Expand each center and increment on every matching boundary pair.

Time and space

O(n²) time · O(1) space

Counterexample to the tempting mistake

Counting only maximal palindromes misses their palindromic interiors.

Prove it again tomorrow

Close this page. Rebuild the state and transition from memory, write a test that exposes the mistake above, then solve a fresh input without looking back. A same-day reread is practice, not proof of retention.

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